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electronics · digital logic · CMOS

CMOS 3-Input XOR Gate

This CMOS 3-input XOR gate circuit implements the parity function Y = A XOR B XOR C with two cascaded sections of a 74HC86 quad XOR IC. The first gate combines A and B and produces intermediate net X. The second gate combines X with C to produce Y. A 5 V VDD supply and ground reference are shown, along with three labeled 5 V logic input sources and a 10 kΩ output load.

類型 電路圖標準 IEEE Std 315 / ANSI Y32.2引擎 schematex-circuit更新時間 2026/9/24
CMOS 3-Input XOR Gate
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需求

“Draw a 5 V three-input XOR using two cascaded 74HC86 gates: 5 V A, B, and C input sources feed the gates, and Y drives a 10 kΩ output load.”

接著試試Add a fourth XOR input stage.Change the supply and input sources to 3.3 V.
這張圖裡有什麼

看懂背後的決策。

01Cascaded XOR stages

U1 produces intermediate net X from A and B, and U2 combines X with C.

02CMOS supply

VDD is supplied at 5 V with node 0 as the return reference.

03Defined inputs

Separate A, B, and C sources make every logic input a connected net.

04Output loading

A 10 kΩ load from Y to ground gives the output a defined connected load.

Use this circuit for a 5 V CMOS three-input parity function built from a 74HC86. Verify input drive levels, fan-out, decoupling, and the specific package pinout before hardware use.

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常見問題

常見問題

What logic function does this circuit implement?

Y is high when an odd number of A, B, and C are high; it is a three-input XOR or odd-parity function.

Why are two 74HC86 gates used?

A 74HC86 contains two-input XOR gates, so one gate forms A XOR B and the next combines that result with C.

What is net X?

X is the intermediate output of the first XOR stage and the first input to the second stage.

Does the 10 kΩ resistor set the logic level?

No. It is an output load to ground; the 74HC86 output still actively drives Y high or low.